A rod of a certain metal is 1.0 m long and 0.6 cm in diameter. Its resistance is 3.0 × 10 -3 ohm. Another disc made of the same metal is 2.0 cm in diameter and 1.0 mm thick. What is the resistance between the round faces of the disc
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Resistivity of the material of the rod $\rho = \frac{\mathrm{RA}}{l} = \frac{3 \times 10^{-3} \pi (0.3 \times 10^{-2})^2}{1} = 27 \times 10^{-9} \pi \Omega \times m$
Resistance of disc $R = \frac{\text{(Thickness)}}{\text{(Area of cross section)}}$
$= 27 \times 10^{-9} \pi \times \frac{\left(10^{-3}\right)}{\pi \times \left(1 \times 10^{-2}\right)^2} = 2.7 \times 10^{-7} \Omega$
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