Published by:
CGP EDU Academic Team
Published on: September 11, 2026
In the adjoining circuit, the battery E 1 has an e.m.f of 12 volt and zero internal resistance while the battery E has an e.m.f of 2 volt. If the galvanometer G reads zero, then the value of the resistance X in ohm is
Text Solution
Verified by ExpertsThe correct answer is:
B
For no current through galvanometer, we have
$\left(\frac{E_{1}}{500+X}\right)^{X} = E$
⇒ ⇒ $\left(\frac{12}{500 + X}\right)^X = 2$
⇒ ⇒ X = 100 Ω Ω
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