50 Ω Ω and 100 Ω Ω resistors are connected in series. This connection is connected with a battery of 2.4 volts. When a voltmeter of 100 Ω Ω resistance is connected across 100 Ω Ω resistor, then the reading of the voltmeter will be
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Equivalent resistance of the circuit $R_{eq} = 100 \Omega$
current through the circuit $i = \frac{2.4}{100} A$
P.D. across combination of voltmeter and 100 Ω Ω resistance $= \frac{2.4}{100} \times 50 = 1.2 \mathrm{V}$
Since the voltmeter and 100 Ω Ω resistance are in parallel, so the voltmeter reads the same value i.e. 1.2V.
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