A wire of resistance 10 Ω Ω is bent to form a circle. P and Q are points on the circumference of the circle dividing it into a quadrant and are connected to a Battery of 3 V and internal resistance 1 Ω Ω as shown in the figure. The currents in the two parts of the circle are
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
In the following figure
Resistance of part PNQ;
and
Resistance of part PMQ;
= 
.
Main Current i = 
So, i 1 = 
and 
.
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