The V-i graph for a conductor at temperature T 1 and T 2 are as shown in the figure. $\left(T_{2} - T_{1}\right)$ is proportional to
Text Solution
Verified by ExpertsC
As we know, for conductors resistance ∝ ∝ Temperature.
From figure R 1 ∝ ∝ T 1 ⇒ ⇒ tan θ θ ∝ ∝ T 1 ⇒ ⇒ tan θ θ = kT 1 … (i)
and R 2 ∝ ∝ T 2 ⇒ ⇒ tan (90 o – θ θ ) ∝ ∝ T 2 ⇒ ⇒ cot θ θ = kT 2 ….(ii)
From equation (i) and (ii) $k(T_2 - T_1) = (\cot \theta - \tan \theta)$
$(T_2 - T_1) = \left(\frac{\cos \theta}{\sin \theta} - \frac{\sin \theta}{\cos \theta}\right) = \frac{(\cos^2 \theta - \sin^2 \theta)}{\sin \theta \cos \theta}$ $-2 \cot 2\theta$
⇒ ⇒ (T 2 – T 1 ) ∝ ∝ cot 2 θ θ
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems