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CGP EDU Academic Team
Published on: September 12, 2026
The plates of a parallel plate capacitor of capacity $5 0 \mu C$ are charged to a potential of $100\,\text{volts}$ and then separated from each other so that the distance between them is doubled. How much is the energy spent in doing so
Text Solution
Verified by ExpertsThe correct answer is:
A
$W_{ext} = \frac{1}{2} C' V'^2 = \frac{1}{2} C V^2$
$=\left(\frac{1}{2}\right)\left(\frac{C}{2}\right)(2V)^2-\frac{1}{2}CV^2=\frac{1}{2}CV^2$
$W_{ext} = \frac{1}{2} \times 50 \times 10^{-6} \times (100)^2 = 25 \times 10^{-2} J$
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