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CGP EDU Academic Team
Published on: September 12, 2026
64 drops of mercury each charged to a potential of 10 V . They are combined to form one bigger drop. The potential of this drop will be (Assume all the drops to be spherical)
Text Solution
Verified by ExpertsThe correct answer is:
A
$V = n^{2/3} v = (64)^{2/3} \times 10 = 160 volt$
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