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CGP EDU Academic Team
Published on: September 12, 2026
The electric potential $V$ is given as a function of distance x (metro) by $V = (5x^{2} + 10x - 9) \mathrm{vol} / t$ . Value of electric field at $x = 1$ is
Text Solution
Verified by ExpertsThe correct answer is:
A
$E = -\frac{dV}{dx} = -\frac{d}{dx}(5x^{2} + 10x - 9) = -10x - 10$
∴ ∴ $(E)_{x=1} = -10 \times 1 - 10 = -20 \text{ V/m}$
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