A charged particle of mass $5 \times 10^{-5} \, \mathrm{kg}…

Physics Electrostatics Potential & Capacitance Electric Field and Potential,Defference,Energy and Dipole Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: September 12, 2026

A charged particle of mass $5 \times 10^{-5} \, \mathrm{kg}$ is held stationary in space by placing it in an electric field of strength $10^{7} \mathrm{N C}^{-1}$ directed vertically downwards. The charge on the particle is

$-20 \times 10^{-5} \, \mu \mathrm{C}$

$- 5 \times 10^{-6} \, \mu C$

$5 \times 10^{-5} \, \mu C$

$20 \times 10^{-5} \, \mu C$

Text Solution

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The correct answer is:

As the particle is stationary net force = 0

$Eq mg+ = 0 q = \frac{-mg}{E} = \frac{-(5 \times 10^{-6})(10)}{10^{6}} = -5 \times 10^{-5} \mu C$

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