Published by:
CGP EDU Academic Team
Published on: September 12, 2026
The average power dissipated in a pure inductor of inductance
when an ac current is passing through it, is
Text Solution
Verified by ExpertsThe correct answer is:
D
In a pure inductor, the power factor is zero because the current lags the voltage by 90 degrees. The average power (C0) dissipated in an AC circuit with a pure inductor is calculated using the formula:
P = V_{rms} I_{rms} imes ext{cos}( heta), where P is the average power, V_{rms} is the root mean square voltage, I_{rms} is the root mean square current, and B8 is the phase difference. Since B8 = 90^ , cos(90^ ) = 0.
Thus, the average power dissipated is:
P = V_{rms} I_{rms} imes 0 = 0.
Therefore, the average power dissipated in a pure inductor when an AC current is passing through it is zero.
P = V_{rms} I_{rms} imes ext{cos}( heta), where P is the average power, V_{rms} is the root mean square voltage, I_{rms} is the root mean square current, and B8 is the phase difference. Since B8 = 90^ , cos(90^ ) = 0.
Thus, the average power dissipated is:
P = V_{rms} I_{rms} imes 0 = 0.
Therefore, the average power dissipated in a pure inductor when an AC current is passing through it is zero.
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