The amount of charge required to liberate 9 gm of aluminium (atomic weight = 27 and valency = 3) in the process of electrolysis is (Faraday's number = 96500 coulombs/gm equivalent)
Text Solution
Verified by ExpertsThe correct answer is:
D
Equivalent weight of aluminium 
So 1 faraday = 96500 C are required to liberate 9 gm of Al.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Water can not be made conducting by adding small amount of any of the following except
The electrochemical equivalent Z of any element can be obtained by multiplying the electrochemical …
A silver and zinc voltameter are connected in series and a current i is passed through them for a t…
To deposit one gm equivalent of an element at an electrode, the quantity of electricity needed is
In an electrolysis experiment, a current i passes through two different cells in series, one contai…
To deposit one liter of hydrogen at 22.4 atmosphere from acidulaled water, the quantity of electric…