A proton of energy 8 eV is moving in a circular path in a uniform magnetic field. The energy of an alpha particle moving in the same magnetic field and along the same path will be
Text Solution
Verified by ExpertsThe correct answer is:
C
Let 
be the mass and the charge of the particle moving in a magnetic field 
, then the energy is given by
where 
is radius of circular path.
For proton 
...(i)
For 
-particle 
From Eqs. (i) and (ii),
we get 
(given)
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