Published by:
CGP EDU Academic Team
Published on: September 12, 2026
The expression for the torque acting on a coil having area of cross-section A, number of turns n, placed in a magnetic field of strength B, making an angle 
with the normal to the plane of the coil, when a current i is flowing in it, will be
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
To find the torque \( \tau \) acting on a coil in a magnetic field, we can use the formula:
\( \tau = nIBA \sin(\theta) \)
where:
- \( n \) = number of turns
- \( I \) = current
- \( B \) = magnetic field strength
- \( A \) = area of the coil
- \( \theta \) = angle between the magnetic field and the normal to the coil
Therefore, the expression for torque is correctly represented by Option A: \( \tau = nIBA \sin(\theta) \).
\( \tau = nIBA \sin(\theta) \)
where:
- \( n \) = number of turns
- \( I \) = current
- \( B \) = magnetic field strength
- \( A \) = area of the coil
- \( \theta \) = angle between the magnetic field and the normal to the coil
Therefore, the expression for torque is correctly represented by Option A: \( \tau = nIBA \sin(\theta) \).
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