A horizontal rod of mass 10 gm and length 10 cm is placed on a smooth plane inclined at an angle of 
with the horizontal, with the length of the rod parallel to the edge of the inclined plane. A uniform magnetic field of induction B is applied vertically downwards. If the current through the rod is 1.73 ampere, then the value of B for which the rod remains stationary on the inclined plane is
A
1.73 Tesla
B
Tesla
C
1 Tesla
D
None of the above
Text Solution
Verified by ExpertsThe correct answer is:
C
The given situation can be drawn as follows
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