A hydrogen like atom of atomic number Z is in an excited state of quantum number 2n. It can emit a maximum energy photon of 204 eV. If it makes a transition to quantum state n, a photon of energy 40.8 eV is emitted. The value of n will be
Text Solution
Verified by ExpertsThe correct answer is:
B
Let ground state energy (in eV) be 
Then from the given condition
From equation (i) and (ii), 
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