A thin semicircular conducting ring of the radius
is falling with its plane vertical in a horizontal magnetic induction
. At the position MNQ, the speed of the ring is
and the potential difference developed across the ring is

Text Solution
Verified by ExpertsThe correct answer is:
D
Induced motional emf in MNQ is equivalent to the motional emf in an imaginary wire MQ i . e.,



Therefore, the potential difference developed across the ring is
with Q at a higher potential.
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