Published by:
CGP EDU Academic Team
Published on: September 12, 2026
For series 
circuit, wrong statement is
A
Applied e.m.f. and potential difference across resistance are in same phase
B
Applied e.m.f. and potential difference at inductor coil have phase difference of 
C
Potential difference at capacitor and inductor have phase difference of 
D
Potential difference across resistance and capacitor have phase difference of 
Text Solution
Verified by ExpertsThe correct answer is:
D
In an LCR series circuit, the relationships between the voltages across different components and the phase differences must be understood properly.
Step 1: In a resistive component (R), the voltage is in phase with the current.
Step 2: In an inductor (L), the voltage leads the current by a phase difference of \( \frac{\pi}{2} \) radians.
Step 3: In a capacitor (C), the voltage lags the current by a phase difference of \( \frac{\pi}{2} \) radians.
Step 4: The potential difference across the resistor and the capacitor will not have a phase difference of \( \frac{\pi}{2} \). Instead, the voltage across the capacitor lags the current, while the voltage across the resistor is in phase with the current.
Conclusion: Therefore, Option D is the wrong statement, as the phase difference between voltage across resistance and capacitor is actually less than \( \frac{\pi}{2} \).
Step 1: In a resistive component (R), the voltage is in phase with the current.
Step 2: In an inductor (L), the voltage leads the current by a phase difference of \( \frac{\pi}{2} \) radians.
Step 3: In a capacitor (C), the voltage lags the current by a phase difference of \( \frac{\pi}{2} \) radians.
Step 4: The potential difference across the resistor and the capacitor will not have a phase difference of \( \frac{\pi}{2} \). Instead, the voltage across the capacitor lags the current, while the voltage across the resistor is in phase with the current.
Conclusion: Therefore, Option D is the wrong statement, as the phase difference between voltage across resistance and capacitor is actually less than \( \frac{\pi}{2} \).
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems