In Millikan's oil drop experiment, an oil drop of mass 
is balanced by an electric field of 
. The charge in coulomb on the drop, assuming 
is
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
C
Robert Millikan performed the experiment to determine the charge on an electron. When a drop is suspended, its weight 
is exactly equal to the electric force applied 
, where 
is electric filed, 
the charge, 
the mass of drop and 
the acceleration due to gravity.
Hence, solving for 
, we get
Given, 
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