Published by:
CGP EDU Academic Team
Published on: September 12, 2026
At Kavalur in India, the astronomers using a telescope whose objective had a diameter of one meter started using a telescope of diameter 2.54 m . This resulted in
Text Solution
Verified by ExpertsThe correct answer is:
A
To understand the effect of changing the diameter of a telescope's objective on its resolving power, we start with the formula for resolving power (R) of a telescope, which is given by:
R = \frac{1.22 \lambda}{D}
where:
R_{new} = \frac{1.22 \lambda}{2.54}
The ratio of the new resolving power to the original resolving power is:
\frac{R_{new}}{R_{old}} = \frac{\frac{1.22 \lambda}{2.54}}{\frac{1.22 \lambda}{1}} = \frac{1}{2.54}
Thus, the resolving power increases by 2.54 times. Therefore, Option A is correct.
R = \frac{1.22 \lambda}{D}
where:
- \lambda is the wavelength of light.
- D is the diameter of the telescope's objective.
R_{new} = \frac{1.22 \lambda}{2.54}
The ratio of the new resolving power to the original resolving power is:
\frac{R_{new}}{R_{old}} = \frac{\frac{1.22 \lambda}{2.54}}{\frac{1.22 \lambda}{1}} = \frac{1}{2.54}
Thus, the resolving power increases by 2.54 times. Therefore, Option A is correct.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The focal lengths of the objective and eye-lens of a microscope are 1 cm and 5 cm respectively. If …
In a compound microscope magnification will be large, if the focal length of the eye piece is
The focal length of the objective lens of a compound microscope is
Microscope is an optical instrument which
Magnifying power of a simple microscope is (when final image is formed at D = 25 cm from eye)
If in compound microscope m 1 and m 2 be the linear magnification of the objective lens and eye len…