A mass of 2 kg is placed on a trolley of 20 kg sliding on a smooth surface. The coefficient of friction between the mass and surface of trolley is 0.25. A horizontal force of 2N is applied to the mass. The acceleration of the system and the frictional force between the mass and surface of trolley are
Text Solution
Verified by ExpertsThe correct answer is:
C
Limiting frictional force = μ μ mg
= 0.25 × 2 × 10 = 5 N
So the block and trolley will not have relative motion for a force of 2N.
Here, 2 = (20 + 2) a
or a = 
Then frictional force = 20 × 0.09n = 1.8 N
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