Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A chain of length l is lying in a smooth horizontal tube such that a fraction of its length h hangs freely and the end touches the ground. At a certain moment the other end of chain is set free. The speed of this end of chain when it slips out of the tube is

Text Solution
Verified by ExpertsThe correct answer is:
D
For hanging part,
mgh – T = mha …….. (i)
and for par in tube,
T = mxa ………….. (ii)
Adding the above equations, we get
mgh = m(h + x)a
or a = 
or
or vdv =
dx
∴ ∴ 
i.e., v = 
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