Two blocks connected by a massless string slide down an inclined plane having angle of inclination as 37 0 . The masses of two blocks are 4 kg and 2 kg with μ μ , as 0.75 and 0.25 respectively.
Text Solution
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For mass M 1
T + M 1 g sin 37 - μ μ 1 M 1 g cos 37 = M 1 a ……… (i)
and for mass M 2
M 2 g sin 37 – T - μ μ 2 M 2 g cos 37 = M 2 a ……… (ii)
Adding the substituting the given values, we get
2g × 0.6 + 4g × 0.6 – 0.25 × 2g × 0.8 – 0.75 × 0.8 = (4 + 2) a
g (1.2 + 2.4 – 0.4 – 2.4)6a
or a = 1.3 ms -2
Using (ii)
9.8 × 0.6 – T – 0.25X 2 × 9.8 × 0.8 = 2 X 13
or T = 11.76 – 3.98 – 2.6
= 5.29 N
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