A bullet moving with a velocity of 100 m/s can just penetrate two planks of equal thickness. The number of such planks penetrated by the same bullet, when the velocity is doubled, will be –
Text Solution
Verified by ExpertsThe correct answer is:
C
Let the thickness of each plank = x then from third equation of motion,
0 = u 2 – 2a (2x)
u 2 = 4ax ...(i)
If velocity is doubled, let n planks are required
then,
0 = (2u) 2 – 2a(hx)
n = 
= 
= 8
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