Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Block A of mass 35 kg is resting on a frictionless floor. Another block B of mass 7 kg is resting on it as shown in figure. The coefficient of friction between the blocks is 0.5 while kinetic friction is 0.4. If a force of 100 N is applied to block B, the acceleration of the block A will be: (g = 10 m s –2 )
Text Solution
Verified by ExpertsThe correct answer is:
A
7 kg body will slide because
F = 100 N >> limiting friction
∴ Friction b/w bodies is kinetic
f k = μ k mg = 0.4 × 7 × 10 = 28N
∴ a = 28/35 = 0.8 m/s 2
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A vessel containing water is given a constant acceleration a towards the right, along a straight ho…
A ship of mass \(3 \times 10^{7} \, \text{kg}\) initially at rest is pulled by a force of \(5 \time…
The mass of a body measured by a physical balance in a lift at rest is found to be m. If the lift i…
Three weights W, 2W and 3W are connected to identical springs suspended from a rigid horizontal rod…
When forces F_1, F_2, F_3 are acting on a particle of mass m such that F_2 and F_3 are mutually per…
The spring balance A reads 2 kg with a block m suspended from it. A balance B reads 5 kg when a bea…