Two mass m and 2m are attached with each other by a rope passing over a frictionless and massless pulley. If the pulley is accelerated upwards with an acceleration 'a', what is the value of T?
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
C
w.r.t. pulley
T – (mg + ma) = ma’ .....(i)
2m : (2 mg + 2 ma) – T = 2ma' .......(ii)
From (i) & (ii)
2T – 2 (mg + ma) = (2 mg + 2 ma) – T
⇒ 3T = 4 (mg + ma) ⇒ T = 
(g + a)
Short trick
T = 
(g + a) = 
(g + a)
= 
(g + a)
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