System shown in figure is released from rest. Pulley and spring is massless and friction is absent everywhere. The speed of 5 kg block when 2 kg block leaves contact with ground is: (Take force constant of spring k = 40 N/m and g = 10 m/s 2 )
A
m/s
B
m/s
C
2 m/s
D
m/s
Text Solution
Verified by ExpertsThe correct answer is:
B
Let x be the extension is spring when 2 kg block leaves the contact with ground. Then kx = 2g
x = 
= 
= 
Now from conservation of energy,
mgx = 
kx 2 + 
mv 2
v = 
= 
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