A rod of length L is rotated in horizontal plane with constant angular velocity ω ω . A mass m is suspended by a light string of length L from the other end of the rod. If the angle made by vertical with the string is θ θ then angular speed, ω ω =
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
D
Radius of horizontal circle of ball = (L + L sin θ θ )
∴ ∴ C.P. Acceleration = (L + L sin θ θ ) ω ω 2 ( Q a = r ω ω 2 )
Here mg = T cos θ θ …….. (i)
and m ω ω 2 (L + L sin θ θ ) = T sin θ θ ……… (ii)
Dividing (ii) by (i)
tan θ θ = 
or ω ω 2 = 
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