Neglecting the masses of the string and pulley and ignoring…

Physics Newton's Laws of Motion Tension and Tension Force MCQ (Single Correct)

Neglecting the masses of the string and pulley and ignoring the friction in the system, we find that

Weights fall freely. Pulley B rotates clockwise and pulley A, C rotate anticlockwise.

The two weights have different accelerations. Pulley C rotates clockwise and B, C rotate anticlockwise.

Acceleration of masses will be zero and the system will be at rest.

Acceleration of masses is equal to g. Pulley A and C rotate clock wise whereas B rotates anticlockwise.

Text Solution

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The correct answer is:

Here m 1 g – T = m 1 a 1

(taking a 1 as downward acceleration of m 1 )

2T – m 2 g = m 2 a 2

(taking a 2 as upward acceleration of m 2 )

and 2T – T = 0 ( Q  mass of pulley is zero)

Thus, T = 0 ∴ ∴ a 1 = a 2 = g

Thus, the masses will have free fall.

Clearly pulley B rotates clockwise and the other pulleys in anticlockwise direction.

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