Two identical blocks P and Q have mass m each. They are attached to two identical spring initially unstretched. Now the left spring (along with P) is compressed by 
and the right spring (along with Q) is compressed by A. Both the blocks are released simultaneously. They collide perfectly inelastically. Initially time period of both the block was T.
(i) The time period of oscillation of combined mass is–
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(i) : They will collide at their mean position because time period of both are same and that is
2 π 
. After collision combined mass is 2m and K eff = 2K. Hence, time period remains unchanged.
(ii) : From conservation of linear momentum we can see that velocity of combined mass just after collision is v = 
.
Since, this is the velocity at mean position.
Hence, v = ω′ A ′
= ω ´A´
or A ′ = 
because ω ' = ω = 
or 
(iii) :
E = 
(2m) v 2 = 
(2m) 
= 
= 
E = 
(2k) 
= 
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