One particle of mass 1 kg is moving along x-axis with velocity 3 m/s and another particle of mass 2 kg is moving along y-axis with 6 m/s. At t = 0, 1 kg mass is at (3m, 0) and 2 kg at (0, 9m). Here x – y plane is horizontal plane-
(i) The center of mass of two particle is moving in a straight line (at t = 0).
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(i) : 
= 
and m 1 = 1kg
= 
and m 2 = 2 kg
Also, initial locations are (3, 0) and (0, 9)
x 1 = 3 + 3t and x 2 = 0
y 1 = 0 and y 2 = 9 + 6t
x cm = 
= 1 + t
y cm = 
= 6 + 4t
y cm = 4x cm + 2
(ii) : t 1 = 
= 1.5 sec. and t 2 = 
= 3 sec
( iii) : x 1 = 3 + 
= 5.25 m and x 2 = 0
y 1 = 0, y 2 = 
18 m
= x cm = 
= 1.75 m
y cm = 
= 12 m
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