ABCD is a vertical frame of mass M. Two strings between block of mass m and frame are ideal and lies in vertical plane. The frame ABCD is placed on horizontal smooth surface and a horizontal force F is applied as shown. Points P and Q are in same vertical line and two strings are of equal length
(i) Minimum force F required to make both string tight is–
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(i) : For minimum force F lower
string just remain tight i.e. T 2 → 0
∴ T 1 cos θ = mg and T 1 sin θ = ma
∴ a = g tan θ ⇒ F = (m + M) g tan θ
(ii) : For minimum force F lower
string just remain tight i.e. T 2 → 0
∴ T 1 cos θ = mg and T 1 sin θ = ma
∴ a = g tan θ ⇒ F = (m + M) g tan θ
(iii) : T 1 cos θ = mg + T 2 cos θ
⇒ (T 1 –T 2 ) cos θ = mg ..............(i)
also (T 1 +T 2 ) sin θ = ma ..............(ii)
from (i) and (ii) 
tan θ = 
But as T 1 = 2T 2 given
∴ a = 3g tan θ
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems