Home Physics Newton's Laws of Motion Coefficeint of Friction A long block A is at rest on a smooth horizo…
Physics Newton's Laws of Motion Coefficeint of Friction MCQ (Single Correct)

A long block A is at rest on a smooth horizontal surface. A small block B (whose mass is half of A) is placed on A at one end and projected along A with a velocity v. The coefficient of friction is μ μ .

A
the block will reach a final common velocity u/3.
B
the work done against friction is 2/3 of initial KE of B.
C
before the blocks reach a common velocity, the acceleration of A relative to B is 2/3 μ μ g.
D
before the blocks reach a common velocity the acceleration of A relative to B is 3/2 μ μ g.

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The correct answer is:
CHECK THE SOLUTION.

(a, b, c)

since F ext of A + B system is zero. Therefore, momentum of A + B system is conserved.

mu = (m – 2m) v or v = u/3.

Work done against friction = Loss is KE = 1/2 mu 2 = 1/2 (2m) (u/3) 2 = .

Force of friction between the blocks = μ μ mg.

Acceleration of A (towards right) =

Acceleration of B (towards right) = μ μ g.

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