Home Physics Newton's Laws of Motion Mix A flat cart of mass m 0 starts moving to the…
Physics Newton's Laws of Motion Mix MCQ (Single Correct)

A flat cart of mass m 0 starts moving to the right due to a constant horizontal force F at t = 0. Sand spills on the flat cart from a stationary hopper. The velocity of loading is constant and is equal to µ kg/sec.

A
Initial acceleration is equal to F/m 0
B
Acceleration at time t is F/ (m 0 + µt)
C
Kinetic energy of loaded cart at an instant is equal to work done by force F up to that instant
D
Momentum of loaded cart at an instant is equal to impulse of force F up to that instant.

Share this question

For Instagram sharing, use “Apps” on mobile or copy the link.

Text Solution

Verified by Experts
The correct answer is:
CHECK THE SOLUTION.

(a, d)

Suppose at an instant 't' velocity of cart be v. Due to the sand falling on the cart, it experiences a retarding force, which is equal to µv. It means net accelerating force on the cart is equal to (F – µv). But at this instant, mass of the loaded cart is equal to (m 0 + µt).

Therefore, acceleration at time t will be equal to . It means, option is wrong.

If in above equation t is substituted as zero, then initial acceleration of the cart is, a 0 =

But at initial moment, speed of flat cart is equal to zero. Hence, the initial acceleration becomes (F/m 0 ). It means, option is correct.

If we consider a system of flat cart and falling sand particles, then sand particles exert a retarding force on the cart which is equal to µv and the cart exerts an accelerating force on sand particles which is also equal to µv. It means the only external force or the only resultant force acting on the system is equal to F.

It means the momentum of the system at any instant t will be equal to impulse of the force F. Hence, option is correct.

The collision of the sand particles with the cart is perfectly inelastic because just after falling on the cart, sand particles start to move horizontally rightward with the cart while just before coming onto the cart, these sand particles have zero horizontal velocity. It means there is a loss of energy during the collision. Hence, kinetic energy of loaded cart at an instant will be less than the work done by the force F up to that instant. Hence, option is wrong.

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Similar Questions

Explore conceptually related problems

CG
CGP Question Assistant Question Bank + AI Help
Hi! Type your question or upload one screenshot. First I will search related questions from CGP Edu Question Bank. If none match, type YES and I will solve it with AI.
Upload only one screenshot at a time. Flow: Question Bank first → If not matched, type YES for AI solution.