Home Physics Newton's Laws of Motion Equilibrium of Forces Three blocks are arranged as shown. ABCD is …
Physics Newton's Laws of Motion Equilibrium of Forces MCQ (Single Correct)

Three blocks are arranged as shown. ABCD is the horizontal plane. Strings are massless and both pulleys stands vertical while the strings connecting blocks m 1 and m 2 are also vertical and perpendicular to each other. The masses m 1 and m 2 are 3 kg and 4 kg respectively. Coefficient of friction between the block m 3 = 10 kg and surface is µ = 0.6, then -

A
The system of blocks can be in equilibrium
B
At equilibrium frictional force on block m 3 is 60 N
C
At equilibrium frictional force on block m 3 is 50 N
D
Total force applied by surface on block m 3 is 50 N

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(a, c, d)

µm 3 g =

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