Home Physics Newton's Laws of Motion Motion of Connected Bodies As shown in figure two blocks A and B of mas…
Physics Newton's Laws of Motion Motion of Connected Bodies MCQ (Single Correct)

As shown in figure two blocks A and B of mass 1kg each are connected by an ideal string that passes over a smooth pulley that is fixed on a smooth fixed wedge as shown. If the ratio of normal reaction on block A and on block B is then –

A
cos θ =
B
sin θ =
C
acceleration of blocks is m/s 2
D
acceleration of blocks is m/s 2

Share this question

For Instagram sharing, use “Apps” on mobile or copy the link.

Text Solution

Verified by Experts
The correct answer is:
CHECK THE SOLUTION.

(a, c)

N A = mg cos and N B = mg cos 53 0

as given = =

∴ cos θ = × ⇒ cos θ =

Now, a = =

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Similar Questions

Explore conceptually related problems

CG
CGP Question Assistant Question Bank + AI Help
Hi! Type your question or upload one screenshot. First I will search related questions from CGP Edu Question Bank. If none match, type YES and I will solve it with AI.
Upload only one screenshot at a time. Flow: Question Bank first → If not matched, type YES for AI solution.