Both the blocks are of same mass and initially at rest. Block B starts swinging.

Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, c)

At mean position: T – mg = mv 2 / λ
T = mg + mv 2 / λ
At extreme position:
T – mg cos θ =
= 0
T = mg cos θ
At any position between extreme and mean

mg – T cos θ = m (a y ) B
(a y ) B = g – 

mg – T = m (a y ) A
(a y ) A = g –T/m
⇒ (a y ) B > (a y ) A
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