Home Physics Newton's Laws of Motion Motion of Connected Bodies In the figure, the blocks are of equal mass.…
Physics Newton's Laws of Motion Motion of Connected Bodies MCQ (Single Correct)

In the figure, the blocks are of equal mass. The pulley is fixed. In the position shown, A moves down with a speed u, and v B = the speed of B.

A
B will never lose contact with the ground
B
The downward acceleration of A is equal in magnitude to the horizontal acceleration of B.
C
v B = u cos θ
D
v B = u/cos θ

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The correct answer is:
CHECK THE SOLUTION.

(a, d)

Never lose contact

Along the string, acc and vel is same

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