A chain of length L and mass m is placed upon a smooth surface (see. Figure). The length of
is L–b. Calculate the velocity of the chain when its end reaches B.

Text Solution
Verified by Experts(i) Where h ; (ii) Similarly, the final potential energy is ; (iii) From the principle of conservation of energy, we know that; (i) ; (iv) Where E k; (i) = 0 Hence, E k; (v) From which follows v
Sol To solve this problem, we use the principle of conservation of energy. Let us denote by
y = 0 the plane
. It will be the reference plane of the potential energy. In changing its position from A to B, the chain's potential energy changes, and as a result, its velocity changes. The potential energy is calculated by integration over the length of the chain. The mass of the chain per unit length is λ =
. The contribution of a piece of length dr to the potential energy is

du = –gh dm = – λ hgdr …...(i)
Where h = r sin θ (see figure). The initial potential energy is, therefore,
u i =
…...(ii)
Similarly, the final potential energy is :
u f =
…...(iii)
From the principle of conservation of energy, we know that:
E k(i) + u i = E k(f) + u f …...(iv)
Where E k(i) = 0 Hence,
E k(f) = u i – u f =
gsin θ (L 2 – b 2 )
mv 2 …...(v)
From which follows
v =
…. (iv)
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