The potential energy for a conservative system is given by U = ax 2 – bx Column-IColumn-II(i) The net force acting on the system[A] b/2a(ii) The equilibrium Position[B] b – 2ax(iii) The potential energy at the Equilibrium position[C] – b2/4a(iv) The equilibrium[D] stable

The potential energy for a conservative system is given by …

Physics Newton's Laws of Motion Equilibrium of Forces MCQ (Single Correct)

The potential energy for a conservative system is given by U = ax 2 – bx

Column-I	Column-II
(i) The net force acting on the system	[A] b/2a
(ii) The equilibrium Position	[B] b – 2ax
(iii) The potential energy at the Equilibrium position	[C] – b2/4a
(iv) The equilibrium	[D] stable

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The correct answer is:

CHECK THE SOLUTION.

(i)-[B], (ii)-[A], (iii)-[C], (iv)-[D]

Sol. F = – = – [2 ax – b] = b – 2 ax

So → (Q)

At equilibrium position

F = 0

∴ x = b/2a

SO → (P)

Equilibrium potential energy

U = – =

So → (R)

= 2a hence = +ve

i.e. system is at stable equilibrium.

So → (S)

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