Initial position of blocks A & B are shown in figure 1. Block A is pulled horizontally with constant velocity v 0 = 10 m/s. Find the time taken by the block B to reach the pulley.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
Sol.
v B = v A cos 
, v B = v ov cos 
: Since the length of string to be constant velocity of both ends of string along the length of string must be equal.
= v B = 
= 
20 = v 0 2 
………….(i)
= let h 2 + (vot) 2 = x 2 2 v 0
2 tdt = 2xdx
R.H.S. = 
= 
= 
= x = 
From (i)
20 = 
20 = h 2 + (v 0 t) 2 – h
(20 + h) 2 = h 2 + (v 0 t) 2 h = 15 m.
(35)
2 – (15) 2 = (v 0 t) 2 1225 – 225 = (v 0 t)
2 t = 
t = 
= 3.162 sec.
T = 
= 
T = 3.162 sec.
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