In a shotput event an athlete throws the shotput of mass 20 kg with an initial speed of 
at 
from a height 3 m above ground. Assuming air resistance to be negligible and acceleration due to gravity to be 
, the kinetic energy of the shotput when it just reaches the ground will be:
Text Solution
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: The situation is as shown in the figure.
Maximum height reached by the shotput is
Here, u 
Potential energy at
H = 3g (3 + 0.1)
Kinetic energy at
Total mechanical energy at H = 620 J + 20 J = 640 J
Let 
is the kinetic energy at G.
Potential energy at G = 0
Total mechanical energy at 
By the law of conservation of mechanical energy between H and G is
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