Physics Work, Energy, Power and Collision Work Done by Constant and Variable Force MCQ (Single Correct)

The mass of a bucket containing water is 10 kg. What is the work done in pulling up the bucket from a well of depth 10 m if water is pouring out at a uniform rate from a hole in it and there is loss of 2kg of water from it while it reaches the top

A
1000 J
B
800 J
C
900 J
D
500 J

Share this question

For Instagram sharing, use “Apps” on mobile or copy the link.

Text Solution

Verified by Experts
The correct answer is:
C

: Gravitational force on bucket at starting position

= mg = 10 × × 10 = 100 N

Gravitational force on bucket at final position

= 8 × × 10 = 80 N

So the average force through out the vertical motion

∴ ∴ Work done = Force × × displacement = 90 × × 10 = 900 J.

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Similar Questions

Explore conceptually related problems

CG
CGP Question Assistant Question Bank + AI Help
Hi! Type your question or upload one screenshot. First I will search related questions from CGP Edu Question Bank. If none match, type YES and I will solve it with AI.
Upload only one screenshot at a time. Flow: Question Bank first → If not matched, type YES for AI solution.