Two skaters, each of mass 70 kg, skate at speeds of 4 m/s in opposite directions along parallel lines 1.5 m apart. As they are about to pass one another they join hands and go into circular path about their common centre of mass. Angular velocity of their motion is:
Text Solution
Verified by ExpertsThe correct answer is:
A
Initial angular momentum about O
= 2 × × MVr = 420 kg kg-m 2 /s
As angular momentum is conserved
Thus 420 = I ω ω
⇒ ⇒ 
= 5.3 radian/second
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Two bodies of masses and have equal kinetic energies. If and are their respective momentum, the…
Work done in raising a box depends on
A light and a heavy body have equal momenta. Which one has greater K.E
A body at rest may have
The kinetic energy possessed by a body of mass m moving with a velocity v is equal to , provided
If the momentum of a body is increased n times, its kinetic energy increases