Similar of cubical shape of edge b are lying on ground. Density of material of slab is δ δ . Work done to arrange then one over the other is
A
(N 2 – 1) b 2 ρ ρ g
B
(N - 1) b 4 ρ ρ g
C
(N 2 - N) b 4 ρ ρ g
D
(N 2 - N) b 4 ρ ρ g
Text Solution
Verified by ExpertsThe correct answer is:
C
C.G. of first slab = 
Weight of each stab = volume × density × g = b 2 ρ ρ g
C.G. of column of slabs
= 
= 
Height of displacement of force
= 
Work done = N × b 2 ρ ρ G × (N - 1) 
= 
(N 2 - N) b 4 ρ ρ g
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