A small block of mass m is released from rest from point D and slides down DGF and reaches the point F with speed v F . The coefficient of kinetic friction between block and both the surfaces DG and GF is μ μ , the velocity v F is
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
B
Here mgy – 
mv F 2 = f 2 s + f 2 s 2
i.e., 
mv F 2 = mgy - μ μ mg cos β β x 1 - μ μ mg cos γ γ s 2
or 
v F 2 = g 
or v F = 
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