A 10 N block is released from rest at A and slides down along the smooth cylindrical surface. The attached spring has a stiffness, k = 30 Nm –1 . If it does not allow the block to leave the surface until θ = 60º, its unstretched length is -
Text Solution
Verified by ExpertsThe correct answer is:
C
N 1 = mg + kx 1 … (1)
mg cos 60 0 – N 2 + kx 2 = 
Block will leave surface if N 2 = 0
+ kx 2 = mg 
… (2)
Conserving energy at A & B
mv 2 = mgR(1 – cos 60 0 ) = 
v = 
from (2) x 2 = 
= 0.166 m
Unstretched length x 0 = R – x 2
= 0.5 – 0.166 = 0.333 m
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