Home Physics Work, Energy, Power and Collision Mix A ping-pong ball of mass m is floating in ai…
Physics Work, Energy, Power and Collision Mix MCQ (Single Correct)

A ping-pong ball of mass m is floating in air by a jet of water emerging out of a nozzle. If the water strikes the ping-pong ball with a speed v and just after collision water falls dead, the rate of mass flow of water in the nozzle is equal to:

A
B
C
D
None of these.

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Text Solution

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The correct answer is:
C

The impact force F = ( Δ Δ p/ Δ Δ t) where Δ Δ p = change of momentum of water of mass Δ Δ m striking the ball a speed v during time Δ Δ t. Since water falls dead after collision with the ping-pong ball

Δ Δ p = Δ Δ m v ⇒ ⇒ F = v upward on the ball

Where = rate of flow of water in the nozzle.

Since the ball is in equilibrium

F – mg = 0 ⇒ ⇒ F = mg

⇒ ⇒ = mg ⇒ ⇒ = .

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