A wooden block of mass 10 gm is dropped from the top of a tower 100 m high. Simultaneously, a bullet of mass 10 gm is fired from the foot of the tower vertically upwards with a velocity of 100 m/s. If the bullet is embedded in it, how high will it rise above the tower before it starts falling? (g = 10 m/s 2 )
Text Solution
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Block and bullet will collide after 1 sec at height 95 m from ground.
Velocity of block before collision = gt = 10 m/s
Velocity of bullet before collision=u–gt=90 m/s
from conservation of linear momentum,
m (–10) + m (90) = 2 mv'
v' = 40 m/s
Thus height raised by the combined mass
h = 
= 
= 80 m
height from tower = 75 m
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