A block of mass m is stationary with respect to a rough wedge as shown in figure. Starting from rest in time t, (m = 1kg, θ = 30º, a = 2 m/s 2 , t = 4s) work done on block-
Column I | Column II |
(i) By gravity (in magnitude) | [A] 144 J |
(ii) By normal reaction | [B] 32 J |
(iii) By friction | [C] 56 J |
(iv) By all the forces | [D] 48 J |
[E] None |
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
Ans.
(i) [E]
(ii) [A]
(iii) [D]
(iv) [B]
Sol. In t = 4 sec, v = at = 8 m/s
S = 
at 2 = 16 m
KE = 
mv 2 = 32 J
From W – E theorem, Total work = 32 J
W g = – mgh = – 160 J
N cos 30º + f sin 30 º – 10 = ma = 2
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