A 20 gm particle is subjected to two simple harmonic motions x 1 = 2 sin 10 t, x 2 = 4 sin (10 t + 
).
Where x 1 and x 2 are in meter and t is in sec -
A
The displacement of the particle at t = 0 will be 2 
m
m
B
Maximum speed of the particle will be 20 
m/s
m/s
C
Magnitude of maximum acceleration of the particle will be 200 
m/s 2
m/s 2
D
Energy of the resultant motion will be 28 J
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, b, c, d)
At t = 0
Displacement x = x 1 + x 2 = 4 sin 
= 2 
m.
Maximum speed Aɷ = 20 
m/s
Maximum acceleration = A ɷ 2 = = 200 
m/s 2
Energy of motion = 
mɷ 2 A 2 = 28 J Ans.
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